10r^2-6r+10=10

Solution for 10r^2-6r+10=10 equation:

10r^2-6r+10=10

We move all terms to the left:

10r^2-6r+10-(10)=0

We add all the numbers together, and all the variables

10r^2-6r=0

a = 10; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·10·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*10}=\frac{0}{20}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*10}=\frac{12}{20}
=3/5
$